Change return value from getAll in case of not parsed query

Fixes https://github.com/phpmyadmin/phpmyadmin/issues/11609

Signed-off-by: Michal Čihař <michal@cihar.com>

2 files changed, 33 insertions, 2 deletions

diff --git a/src/Utils/Query.php b/src/Utils/Query.php
index d76e6bb..3698f1c 100644
--- a/src/Utils/Query.php
+++ b/src/Utils/Query.php
@@ -380,7 +380,7 @@ class Query
         $parser = new Parser($query);
 
         if (empty($parser->statements[0])) {
-            return array();
+            return static::getFlags(null, true);
         }
 
         $statement = $parser->statements[0];
diff --git a/tests/Utils/QueryTest.php b/tests/Utils/QueryTest.php
index 8455dee..46c89ef 100644
--- a/tests/Utils/QueryTest.php
+++ b/tests/Utils/QueryTest.php
@@ -251,7 +251,38 @@ class QueryTest extends TestCase
 
     public function testGetAll()
     {
-        $this->assertEquals(array(), Query::getAll(''));
+        $this->assertEquals(
+            array(
+                'distinct' => false,
+                'drop_database' => false,
+                'group' => false,
+                'having' => false,
+                'is_affected' => false,
+                'is_analyse' => false,
+                'is_count' => false,
+                'is_delete' => false,
+                'is_explain' => false,
+                'is_export' => false,
+                'is_func' => false,
+                'is_group' => false,
+                'is_insert' => false,
+                'is_maint' => false,
+                'is_procedure' => false,
+                'is_replace' => false,
+                'is_select' => false,
+                'is_show' => false,
+                'is_subquery' => false,
+                'join' => false,
+                'limit' => false,
+                'offset' => false,
+                'order' => false,
+                'querytype' => false,
+                'reload' => false,
+                'select_from' => false,
+                'union' => false,
+            ),
+            Query::getAll('')
+        );
 
         $query = 'SELECT *, actor.actor_id, sakila2.film.*
             FROM sakila2.city, sakila2.film, actor';